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From the previous calculations, we know that the: EvaporationLosses = 0.442kg/s DriftLosses = 0.0239kg/s In a continuous bleed system, the amount of water where all the contaminates can reside is by the drift which takes some of the contaminates away and the makeup water that equal the blowdown., this becomes: COC = (EvaporationLoss + DriftLoss + Bleed) / (DriftLoss + Bleed) Bleed = (EvaporationLosses - [(COC - 1) x DriftLosses]) / ((COC - 1)) Thus, assuming the same 1000 kW heat rejection system with a system design COC of 6, the blowdown required would be: Bleed = (0.442kg/s-[(6-1)x0.239kg/s]) / (6-1) = 0.0645kg/s Note that the system may be shut down and drained as a full blowdown or water continuously released as bleed during cooling tower operation

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